(49x^2+28x+4)/(7x-3)=0

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Solution for (49x^2+28x+4)/(7x-3)=0 equation: 



(49x^2+28x+4)/(7x-3)=0



Domain of the equation: (7x-3)!=0

We move all terms containing x to the left, all other terms to the right

7x!=3

x!=3/7

x!=3/7

x∈R



We multiply all the terms by the denominator


(49x^2+28x+4)=0

We get rid of parentheses

49x^2+28x+4=0

a = 49; b = 28; c = +4;
Δ = b2-4ac
Δ = 282-4·49·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-28}{98}=-2/7$

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